Calculate d(delta)Hrxn for: Ca(s) + 1/2 O2 (g) + CO2 (g) yields CaCO3 (s) given

Question

Calculate d(delta)Hrxn for: Ca(s) + 1/2 O2 (g) + CO2 (g) yields CaCO3 (s)
given the following set of reactions: Ca (s) + 1/2 O2 (g) yields CaO (s) dHrxn = -635.1 kJ CaCO3 (s) yields CaO (s) + CO2 (g) dHrxn= 178.3 kJ

Calculate d(delta)Hrxn for: Ca(s) + 1/2 O2 (g) + CO2 (g) yields CaCO3 (s)
given the following set of reactions: Ca (s) + 1/2 O2 (g) yields CaO (s) dHrxn = -635.1 kJ CaCO3 (s) yields CaO (s) + CO2 (g) dHrxn= 178.3 kJ

Calculate d(delta)Hrxn for: Ca(s) + 1/2 O2 (g) + CO2 (g) yields CaCO3 (s)
given the following set of reactions: Ca (s) + 1/2 O2 (g) yields CaO (s) dHrxn = -635.1 kJ CaCO3 (s) yields CaO (s) + CO2 (g) dHrxn= 178.3 kJ

Ca(s) + 1/2 O2 (g) + CO2 (g) yields CaCO3 (s)
given the following set of reactions: Ca (s) + 1/2 O2 (g) yields CaO (s) dHrxn = -635.1 kJ CaCO3 (s) yields CaO (s) + CO2 (g) dHrxn= 178.3 kJ

Explanation / Answer

Apply hess law

Ca (s) + 1/2 O2 (g) --> CaO (s) dHrxn = -635.1 kJ

CaCO3 (s) --> CaO (s) + CO2 (g) dHrxn= 178.3 kJ

if we want

Ca(s) + 1/2 O2 (g) + CO2 (g) --> CaCO3 (s)

First, invert equation (2)

CaO (s) + CO2 (g) --> CaCO3 (s) dHrxn= -178.3 kJ

Now add new equation and (1)

Ca (s) + 1/2 O2 (g) --> CaO (s) dHrxn = -635.1 kJ

CaO (s) + CO2 (g) --> CaCO3 (s)   dHrxn= -178.3 kJ

Ca (s) + 1/2 O2 (g) + CaO (s) + CO2 (g) --> CaO (s) CaCO3 (s) dHrxn = -635.1-178.3

cancel common terms

Ca (s) + 1/2 O2 (g) + CO2 (g) --> CaCO3 (s) dHrxn = -813.4 kJ

which is what we wanted

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