These problems are similar to what you are doing In lab, but not identical if yo
ID: 903377 • Letter: T
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These problems are similar to what you are doing In lab, but not identical if you need additional help in doing these problems refer to your General Chemistry textbook tor information To receive full credit you must SHOW ALL YOUR WORK for each answer you must give your final answer with the correct number of significant figures -nAcl(S) + - H SO (aq) + - Na SO (aq) If 35. g of NaCL are used, and only 8.6 g of HCL are isolated, what is the percent yield of HCL? If only It g of HO are obtained how many grams of Na,SO must also have formed?Explanation / Answer
1. d. 2NaCl + H2SO4 = 2HCl + Na2SO4
e. Molar mass of NaCl = 58.44 g
Molar mass of HCl = 36.46 g
Molar mass of Na2SO4 = 124.04 g
Molar mass of H2SO4 = 98.079 g
2 mol or 58.44*2= 116.88 g NaCl reacts completely with 98.079 g H2SO4
So, 35 g NaCl reacts completely with = 98.079 * 35/116.88 g H2SO4
= 29.37 g H2SO4
f. 116.88 g NaCl reacts to completely to give 2 * 36.46 = 72.92 g HCl
So, 35 g NaCl reacts to completely to give = 72.92*35/116.88 g HCl
= 21.84 g HCl
% of yield = (8.6/21.84) * 100 = 39.4 %
g. When 72.92 g HCl forms, 124.04 g Na2SO4 forms
When 8.6 g HCl forms, 124.04*8.6/72.92 or 14.63 g Na2SO4 forms
Ans: 14.63 g Na2SO4
2. a. Balanced equation: B2H6 + 6 H2O = 2 H3BO3 + 6 H2
Molar mass of B2H6 = 27.67 g
Molar mass of H3BO3 = 61.83 g
27.67 g B2H6 reacts to give 123.66 g H3BO3
So, 28.16 g B2H6 reacts to give = 123.66 * 28.16/27.67= 125.85 g H3BO3
3.a. 2Ca + O2 = 2CaO
b. Molar mass of Ca = 40.078 g
Molar mass of CaO= 56.07 g
80.156 g Ca gives 112.14 g CaO
So, 5.64 g Ca gives = 112.14 * 5.64/80.156 = 7.89 g CaO = 7.89/56.07 mol of CaO = 0.14 mol of CaO
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