Write nuclear equations for the following process: krypton-81 undergoes beta dec

Question

Write nuclear equations for the following process:

krypton-81 undergoes beta decay                 b) alpha decay of uranium-238

electron capture of lead-206                        d) positron emission of radium-226   

neutron bombardment of zirconium-99         f) thorium-230 decays a radium isotope     

56

   Fe has a mass defect of 0.58872 amu. What is its binding energy per nucleon (kJ/nucleon)?

            26

Carbon-14 decays as follows:

                      14            0            14

                              C   à e   +    N   

                                      6             -1              7

   isotopic masses are 14.00307 for nitrogen-14 and 14.00324 for carbon-14. What energy change (kJ/moles) occurs in the beta decay of C-14?  

Explanation / Answer

There are multiple questions here . i am allowed to answer only 1 at a time. I will answer 2 question for you since 2 and 3 are similar. Please ask other as different question.

2.
mass defect = 0.58872 amu = 0.58872*1.673*10^-27 Kg=9.85*10^-28 Kg
Energy = mass defect * (c)^2
    =(9.85*10^-28 ) * (3*10^8)^2
    =8.86*10^-11 J
     =8.86*10^-14 KJ

number of nucleion = 56
So,
Binding energy per nucleon = (=8.86*10^-14 )/56 =1.6*10^-12 KJ/nucleon

3.
delta m = 14.00324 - 14.00307=0.00017 u
    = 0.00017 *1.673*10^-27 Kg=2.8441*10^-31 Kg
Energy = mass defect * (c)^2
    =(2.8441*10^-31 ) * (3*10^8)^2
    =2.56*10^-14 J
     =2.56*10^-17 KJ

For 1 mol it will be, 2.56*10^-17 * 6.022*10^23 KJ/mol=1.54*10^7 KJ/mol

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