Write the balanced molecular equation for the neutralization reaction between Ba

Question

Write the balanced molecular equation for the neutralization reaction between Ba(OH)2 (a strong base) and HCl (a strong acid).

The lab assistant has prepared for you a 0.378 M solution of Ba(OH)2 and a 0.399 M solution of HCl. What volume of HCl will be required to exactly neutralize 14.0 mL of the Ba(OH)2 solution?

You neutralize 14.0 mL of the Ba(OH)2 solution with this required volume of the HCl solution in a 250 mL beaker which has a mass of 103.3855 g. You heat the solution to drive off all the water, leaving only solid BaCl2. what mass of BaCl2 do you expect to find in the residue?

You find that the beaker plus the residue has a mass of 104.3628 g. What is your percent yield of BaCl2?

Explanation / Answer

1) Ba(OH)2   + 2 HCl      -------------> BaCl2     +     2H2O

                     Ba(OH)2    +          2 HCl      ------------->     BaCl2     +      2H2O

millimioles 14x.378 =5.292          

we need millimoles of HCl = 2x milliomoles of Ba(OH)2 = 2x5.292 =10.584 millimoles

Volume of NaOH solution needed = 26.52 Ml

3) The expected moles of BaCl2 ( millimioles ) 14x.378 =5.292 = 1.100 grams

The actual mass of the residue = 104.3628 g -103.3855 g. = 0.9773

% yield = (actual mass /expected mass)x100 = {.9773/1.1 } x100 = 88.8 %

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