Question 17 Calculate the increase of entropy (in J/K) when 73 g of ice melts at
ID: 904799 • Letter: Q
Question
Question 17 Calculate the increase of entropy (in J/K) when 73 g of ice melts at 0 degree C and 1 atm. (The heat of fusion for ice is 6,000 J/mol.) Question 18 Calculate the change in entropy (in J/K) when 34.0 g of water is heated from 12.4 degree C to 70.5 degree C at 1 atm. (The specific heat is 4.184 J/(g-K).) Question 19 Calculate the change in entropy (in J/K) when 66.6 g of nitrogen gas is heated at a constant pressure of 1.50 atm from 22.8 degree C to 83.5 degree C. (The molar specific heats are Cv is 20.8 J/(mol-K) and Cp is 29.1 J/(mol-K) .)Explanation / Answer
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17.
latent heat of fusion of ice, L = 333.55 J/g
Q = m*L
= 73g * 333.55 J/g
=24349.15 J
T= 0 oC = 273 K
delta S = Q/T
= 24349.15/ 273
= 89.2 J/K
Answer: 89.2 J/K
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