0.801 grams of sodium hydroxide (NaOH) are measured into a 250 mL volumetric fla

Question

0.801 grams of sodium hydroxide (NaOH) are measured into a 250 mL volumetric flask, which is then diluted to the mark with water. 10.0 mL of the sodium hydroxide solution is transferred to a 100 mL graduated cylinder, which is then filled up all the way with water. What is the final concentration of the solution in the graduated cylinder? 0.801 grams of sodium hydroxide (NaOH) are measured into a 250 mL volumetric flask, which is then diluted to the mark with water. 10.0 mL of the sodium hydroxide solution is transferred to a 100 mL graduated cylinder, which is then filled up all the way with water. What is the final concentration of the solution in the graduated cylinder? 0.801 grams of sodium hydroxide (NaOH) are measured into a 250 mL volumetric flask, which is then diluted to the mark with water. 10.0 mL of the sodium hydroxide solution is transferred to a 100 mL graduated cylinder, which is then filled up all the way with water. What is the final concentration of the solution in the graduated cylinder?

Explanation / Answer

Given :

Mass of NaOH = 0.801 g

Volume = 250 mL

Calculation of molarity of stock solution.

[NaOH]= moles NaOH/ Volume of solution L

= (0.801 g /molar mass of NaOH ) / 0.250 L

= 0.801g / 39.9969 mol /0.250 L

= 0.020027 mol / 0.250 L

= 0.0801 M

Now we have M1 = 0.0801 M , V1 = 10 mL

V2 = 100 mL , M2 = ?

We use dilution formula

M1V1 = M2 V2

M2 = M1V1 / V2

= 0.0801 M x 10 mL / 100 mL

= 0.008011 M

Molarity of final solution = 0.008011 M

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