1. Using the average observed rotation for 15% sucrose, calculate it\'s specific

Question

1. Using the average observed rotation for 15% sucrose, calculate it's specific rotation. 2. Using the average observed rotation for 30 % sucrose, calculate it's specific rotation. 3. Compare the above values to the accepted literature value for the specific rotation of sucrose and calculate the percent difference
Evy DATA TABLES Part I Specific Rotation of Sucrose 15% sucrose sample los.os Run 1 Run 2 Run 3 Average Sample height (cm) Anglesample () Angle of rotation, (*) -Anglesample-Angleblank 11.45 | g,“ 18-68 | 9.83 | 11.45 8-4 Cli.-103 "-4 30% sucrose sample Angleblank ()101 94 Run 1 Run 2Run 3Average Sample height (cm) lo Anglesampm(*) =Angleampie-Angleblank | 21.14 | 21.97 | 21.73 Angle of rotation, a () 21-23 21-146 Record Parts I and Ill in your laboratory notebook. DATA ANALYSIS Part I Specific Rotation of Sucrose 1. Using the average observed rotation for 15% sucrose, calculate its specific 2. Using the average observed rotation for 30% sucrose, calculate its specific 3. Compare the above values to the accepted literature value for the specific

Explanation / Answer

1) we know that

[]lT = /lc

[]lT = specific rotation

= average rotation = 9.93

l = path length in dm = 10cm = 1dm

c= concentration in g/ mL = 15g / 100mL = 0.15 g / mL

so []lT = /lc = 9.93 / 1X 0.15 = 66.2

2) 30% sucrose solution

we know that

[]lT = /lc

[]lT = specific rotation

= average rotation = 22.146

l = path length in dm = 10cm = 1dm

c= concentration in g/ mL = 30g / 100mL = 0.3 g / mL

so []lT = /lc = 22.146 / 1X 0.3 = 73.82

3) Compare the above values to the accepted literature value for the specific rotation of sucrose and calculate the percent difference

The literature value is 66.5 (specific rotation)

(a) 15% sucrose solution

Calcualted = 66.2

Difference = 66.5 - 66.2 = 0.3

so % difference = 0.3 X 100/ 66.5 = 0.451%

(b) For 30% solution

Calculated = 73.82

difference = 73.82- 66.5 = 7.32

% difference = 7.32 X 100 / 66.5 = 11%

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