please help urgent must show work please Sher ll or work for full credit 1 Calcu

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Sher ll or work for full credit 1 Calculate the energy and frequency of light that is emitted when un excited electron in the hydrogen Name: atom falls from a 5 to n-2? (R-2.18 x 10-) (h-663 x10 J.s) 2. A 32.5 g piece of aluminum (which has a molar heat capacity of 24.03 JAC-mol) is heated to 82.4°C and dropped into a calorimeter ccetaining water (specilie heat capacity of waicr is 4.13g'C) initially at 22.1°C. The final temperature of the water is 24.2 Ignoring significant figures, calculate the mass of water in the calorimeter

Explanation / Answer

E = - RH( 1/nf2 - 1/ni2)

And once we know the value of E, we can combine the two equations

E = hv    and     v = c /wavelength    to get the equation     E = hc/wavelength

where constant h =  6.626 X 10-34 J s/photon  and constant c = 2.9979 X 108 m/s

So, first let's find the value of E:

E = (-2.18 X 10-18 J)(1/22 - 1/52)

E = - 0.4578 X 10-18 J

Since this photon is moving down in energy levels and the value of E is negative...

Radiation was emitted.

Now, let's find the wavelength

since   E = hc/wavelength,     wavelength = hc/ E, so

wavelength = (6.626 X 10-34 J s/photon)(2.9979 X 108 m/s)/ (-0.4578X 10-18 J/photon)

wavelength = - X 10-18 m,

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