Consider a different analyte for this exercise. Citric acid is found in many fru

Question

Consider a different analyte for this exercise. Citric acid is found in many fruits and fruit juices. Sodium hydroxide (NaOH) is the titrant and citric acid (H3C6H5O7) the analyte according to the following balanced chemical equation.

Complete the following table for this titration.

Data Table P2: Titration of citric acid in orange juice with sodium hydroxide.

concentration of OH? 0.0762 M volume orange juice 8.65 mL mass orange juice 8.79 g volume of OH? solution 22.44 mL mmol of OH? mmol mmol of H3C6H5O7 mmol mass of H3C6H5O7 g mass % of H3C6H5O7 in orange juice % molarity of H3C6H5O7 in orange juice M

Explanation / Answer

H3C6H5O7 + 3 OH C6H5O73 + 3 H2O

from the reaction

3 mol OH- = 1 mole H3C6H5O7

No of mole of OH- = 22.44/1000*0.0762 = 0.001709928 mol

millimole(mmol) of OH- = 1.71 mmol

therefore

No of moles of H3C6H5O7(Citric acid) = 0.001709928/3 = 0.00057 mol

millimole(mmol) of H3C6H5O7(Citric acid) = 0.57 mmol

molarity of H3C6H5O7 in orange juice = 0.00057 / 0.00865 = 0.066 M

mass of H3C6H5O7(Citric acid) = 0.00057 * 192.12 = 0.11 grams

mass % of H3C6H5O7 in orange juice = mass of H3C6H5O7 / mass of juice

    = 0.11/8.79*100 = 1.2514%

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.