Among the compounds represented by the constitution 2-bromo-1,3-pentadiene, ther
ID: 910232 • Letter: A
Question
Among the compounds represented by the constitution 2-bromo-1,3-pentadiene,
there are a total of 2 stereoisomers and both are optically active.
there are a total of 2 stereoisomers and neither is optically active.
there are a total of 4 stereoisomers; two are optically active and two are not.
there are a total of 4 stereoisomers and all are optically active.
there are a total of 4 stereoisomers and none is optically active.
a.there are a total of 2 stereoisomers and both are optically active.
b.there are a total of 2 stereoisomers and neither is optically active.
c.there are a total of 4 stereoisomers; two are optically active and two are not.
d.there are a total of 4 stereoisomers and all are optically active.
e.there are a total of 4 stereoisomers and none is optically active.
Explanation / Answer
The structure of 2-bromo-1,3-pentadiene is
Br
l
H2C = C - HC = CH - CH2 - CH3
For this compound
(1) there is no chiral center
(2) there is no plane of symmetry
(3) Mirror image is possible but not superimposable
So based on these observations there are two possible stereoisomers, each of which would be an enantiomer of one another. Also said it was a chiral molecule that means it is optically active.
Therefore option (a)
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