Question 4 (20 points) A 35.55 L sample of a gas at 154 3 K and exactly one atm,

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Question 4 (20 points) A 35.55 L sample of a gas at 154 3 K and exactly one atm, is compressed to 10.87 L and its temperature (handed to 307.3 K What Is the final pressure (In atm), Report your answer to two (2) decimal places Do not include units (atm) In your answer Your Answer Answer Save Question 5 (20 points) A unknown with a heat of vaporization of 15.8 kJ/mol has a vapor pressure of 0 495 atm at 218 9 K What is the normal boning point in K) of the unknown, Report your answer to one (1) decimal place Do not include units (K) in your answer Your Answer. Answer

Explanation / Answer

V1 = 35.5 L

T1 = 154.3 K

P1 = 1 atm

V2 = 10.87 L

T2 = 307.3 K

P2 = ?

Apply ideal gas law relationships

P1*V1/T1 = P2*V2/T2

P2 = P1*(V1/V2)*(T2/T1)

P2 = 1*(35.55/10.87)*(307.3/154.3) = 6.513 atm

5)

H = 13.8 kJ/mol

P = 0.495 atm and T = 218.9 K

Find T = ? when P = 1 atm

Apply Clasius Clapeyron equation

ln(P2/P1) = H/R(1/T1-1/T2)

ln(1/0.495) = 13800/8.314(1/218.9 - 1/T2)

Solve for T2

T2 = 241.3K = -31.72 °C

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