Answer the following questions assuming that m(s) could have three values rather
ID: 911319 • Letter: A
Question
Answer the following questions assuming that m(s) could have three values rather than two and that the rules for n, l, and m(l) are the normal ones.
a.) How many electrons would an orbital be able to hold?
b.) How many elements would the first and second periods in the periodic table contain?
c.) How many elements would be contained in the first transition metal series?
d.) How many electrons would the set of 4f orbitals be able to hold?
Answers:
a.) 3 b.) 15 c.) 15 d.) 21
!!!!!Please explain why the answers are the answers for each part!!!!! (I'm a very confused A.P. Chem student)
Explanation / Answer
a.) How many electrons would an orbital be able to hold?
An orbital must able only two electrons.
b.) How many elements would the first and second periods in the periodic table contain?
When n =1 it is first energy state, for n =1 l has values l=0 only so l=o ---> s orbital which can hold only 2 electrons.so the number of elements in first period are two.
When n = 2 it is second energy state, for n = 2 l has values l=0,1
so l=o ---> s orbital which can hold only 2 electrons.so the number of elements in are two.
l=1 ---> p orbital which can hold only 6 electrons.so the number of elements in are six.
Therefore there ara a total of 2+6 = 8 elements.
c.) How many elements would be contained in the first transition metal series?
transition metals are the d-block elements.first transition metal series is the 3d series.In d orbitals there are a maximum of 10 electrons so the number of elemnts in the 3d series are 10.
d.) How many electrons would the set of 4f orbitals be able to hold?
f orbital has 7 sub-orbitals & each orbital has a maximum of 2 electrons so maximum number of electrons in f orbital are 2x7 = 14
So the maximum number of electrons are 14.
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