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Status :      1    1    2    9:00 PM Chemical Formulas Scientific Notation Periodic Table Tables

For the following reaction, 29.6 grams of diphosphorus pentoxide are allowed to react with 9.89 grams of water.

diphosphorus pentoxide (s) + water (l) phosphoric acid (aq)

What is the maximum amount of phosphoric acid that can be formed?  grams
What is the FORMULA for the limiting reagent?

What amount of the excess reagent remains after the reaction is complete?  grams

Explanation / Answer

m = 29.6 g of P2O5

m = 9.89 g of H2O

MW of P2O5 = 283.89

MW of H2O = 18

mol of P2O5 = mass/MW = 29.6/283.89 = 0.104265 mol of P2O5

mol of H2O = mass/M" = 9.89/18 = 0.5494 mol of H2O

limiting reactant

P2O5 + 3H2O --> 2H3PO4

since 0.5494 mol of H2O are present, we can react with 0.5494/3 = 0.18313 which we do not have

so, P2O5 is the limitng reactant

maximum amount:

0.104265 mol of P2O5 will react to form 3*0.104265 = 0.312795

mass of H3PO4 = mol*¨MW = 0.312795*98= 30.65391 g of H3PO4

Excess reagent:

Mol left = 0.5494 - 3*0.104265 = 0.23660 mol

mass = 0.23660*18 = 4.2588 g of H2O

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