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The standard reduction potential for Fe^3+ (aq) | Fe(s) electrode is -0.036 V. a

ID: 912237 • Letter: T

Question

The standard reduction potential for Fe^3+ (aq) | Fe(s) electrode is -0.036 V. and for the Fe^2 +(aq) | Fe(s) electrode it is -0.4402 V. The standard oxidation potential for the Fe(s) | Fe^2+ half cell is The cell potential for the Fe(s) | Fe^2+ (aq) || Fe^3+ (aq) | Fe(s) is A positive cell potential indicates that the chemical reaction in the cell can be used to generate electrical work. Can this reaction be used to generate work? Does the potential of the Fe^3+ (aq) | Fe(s) electrode depend on the size of the iron electrode?

Explanation / Answer

The standard reduction potential for Fe(+3)(aq)|Fe(s) is -0.036 V and for Fe(+2)(aq)|Fe(s) is -0.4402 V.

Fe(+3)(aq) + 3e- -> Fe(s); E0(Fe(+3)|Fe(s)) = -0.036 V
Fe(+2)(aq) + 2e- -> Fe(s); E0(Fe(+2)|Fe(s)) = -0.4402 V.

(i)
The standard oxidation potential for Fe(s)|Fe(+2) half cell, E0(Fe(s)|Fe(+2)) = (-)E0(Fe(+2)|Fe(s))= -(-0.4402) = 0.4402 V

(ii)
The cell potential for Fe(s)|Fe(+2)(aq)||Fe(+3)(aq)|Fe(s) = E0(Fe(+2)|Fe(s)) - E0(Fe(+3)|Fe(s)) = -0.036 V -(-0.4402V) = 0.4042 V

(iii)
A positive cell potential indicates that the chemical reaction in the cell can be used to generate electrical work.
Can this reaction be used to generate work? yes
It can be used to move electrons around the circuit.

(iv)
Does the potential of the Fe(+3)(aq)|Fe(s) electrode depends on the size of the iron electrode?

No,
potential depends only on type of ions and concentration of ions in solution by Nerst equation.

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