GIVEN: The concentration of sulfuric acid (H_2S0_4) is 98% by weight. Its specif
ID: 913335 • Letter: G
Question
GIVEN: The concentration of sulfuric acid (H_2S0_4) is 98% by weight. Its specific gravity is 1.86. FIND: What is its molar concentration Atomic weight: Hydrogen (H) = 1, Sulfur (S) = 16, and Oxygen (O) = 32. GIVEN: Chlorine concentration is 1.5 mg/L.. Its specific gravity is 1.02. FIND: Convert this concentration to ppm. GIVEN: River contains toxic chemical at the concentration of 40 mg/mL. Its specific gravity is 1 FIND: Convert this concentration to ppm. Which one has highest molar concentration Atomic weights: Sodium (Na) = 23, Hydrogen (b 1, Sulfur (S) = 16, Oxygen (0) = 32, Chloride (Cl) = 35.5. 150 g NaOH in 3.5 L 5.2 g H_2S0_4 in 30 mL 0.21 kg NaCI in 5L 5.5 g HCI in 100 mLExplanation / Answer
1) sp gravity of sulfuric acid=1.86=density of acid /density of water= density of acid /1g/ml
Density=1.86g/ml
Conc =98% by wt
So actual mass of sulfuric acid=98% of 1.86g/ml=0.98*1.86=1.82 g/ml
[molar mass of acid]=H2SO4=2-1+32+16*4=97g/mol]
Molar concentration=1.82g/molar mass of acid=(1.82g/ml)/(97g/mol)=0.019moles/ml=0.0188 moles/ml * 1000ml/L=18.8 mol/L(answer)
2)sp gravity=1.02
Density=1.02g/ml=1.02g/ml*1000ml/L=102 0g/L
Conc=1.5mg/L
ratio of chlorine=(1.5mg/L)/(1020 g/L)=1.5 mg/1020g
ppm=1.5 *1000 ug/1020g=1.47 ug/g(answer)
3)a)150g NaOH in 3.5 L
Moles of NaOH=150g/molar mass of NaOH=150g/40g/mol=3.75 moles
[molar mass of NaOH=23+16+1=40 g/mol]
Molar conc=3.75mol/3.5L=1.071 mol/L
b)moles of H2SO4=5.2g/molar mass
molar mass of H2SO4=2*1+32+4*16=97g/mol
moles=5.2g/97g/mol=0.053moles
molar conc=0.053 moles/30 *10^-3 L=1.76 mol/L
c)0.021kg=21g
moles of NaCl=21g/molar mass=21g/58.5g/mol=0.358 mol
molar cons=0.358 mol/5L=0.071 mol/L
d) moles of HCl=5.5 g/molar mass=5.5g/36.5 g/mol=0.151 mol
molar conc=0.151 mol/100*10^-3L=1.51 mol/L
1.76 mol/L is the highest molar conc of H2SO4
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