RATE LAW PROBLEM. ITS PROBLEM P3-10, sorry the image is big. Answer part 1, 2, 3
ID: 913627 • Letter: R
Question
RATE LAW PROBLEM. ITS PROBLEM P3-10, sorry the image is big. Answer part 1, 2, 3, 4, & 5 please. 1) -rA = kCA 2) -rA = kCACB^1/2 This is the form I want it in please and do all the parts.
mouiiker to r coefficient is oven temperature is Tai suggests ransfer coefficie ling? (b) Buzz Lightyear says, "No Bob," and suggests Iat t lIU 20 times greater. What are the tradeoffs of oven versus boi Hint: View the YouTube video (www.youtube.com) made by the chen boil the potato in water at 100°C because the heat transfer coekerto chemical by Bob the Builder and Friends. Tye in .Chemicalreactor" to narrow ga Potato You can also access it directly from a link in Chapter 3 Summary Nor search ns assuming each reaction fol- tion engineering students at the University of Alabama, entitled Bak rea. er 3 Summary Notes on the actor" to narrow your search Web site at www.umich.edub-essen.] lows an elementary rate law P3-10 Xa) Write the rate law for the following reactions assuminge C,H, +102-CH2-CH2 CH+02 CH2-CH2 (3) (CH,),COOC(CH,)3-CH, +2CH,COCH, (CH3),COOCCH)C2Hs + 2CH,COCH (5) CH,COOC,H, +C,HHCH COOC,H,+C,H,OH P3-11 (a) Write the rate law for the reaction 2A + B C if the reaction (1) is second order in B and overall third orderExplanation / Answer
The rate law forms would be, with k being the rate constant,
(1) -dC2H6]/dt = k[C2H6]
(2) -d[C2H4]/dt = -1/2d[O2]/dt = k[C2H4][O2]^1/2
(3) -d[(CH3)3COOC(CH3)3]/dt = k[(CH3)3COOC(CH3)3]
(4) -1/nd[C4H10]/dt = k[C4H10]^n
(5) -d[CH3COOC2H5]/dt = -d[C4H9OH]/dt = k[CH3COOC2H5][C4H10]
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