How much water (gpm) must be continually added to the wet scrubber shown in Figu

Question

How much water (gpm) must be continually added to the wet scrubber shown in Figure 2 in order to keep the unit running Each of the streams is identified by a number located in a diamond symbol. Stream 1 is the recirculation liquid flow stream back to the scrubber and it is 20 gallons per minute (gpm). The liquid being withdrawn for treatment and disposal (stream 4) is 2 gpm. Assume that inlet gas stream (number 2) is completely dry and that the outlet stream (number 6) has 10 Ib_m/min of moisture evaporated in the scrubber. The water being added to the scrubber is stream number 5.

Explanation / Answer

The net incoming flow must be the same

Stream 1 + Stream 2 + Stream 3 + Stream 4 + Stream 5 + Stream 6 = 20 gallons ( which is the circulating flow by Stream 2 in order for proper functioning)

20 gallons per minute + 0 + 2 - 2 - 10 lbm/mim + Stream 5 = 20 gallons per minute

Hence stream5 will be equal to 10 lbm/min, it must compensate for the evaporating water which is going in vapor phase in order for perfect functioning of machine

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.