NAD absorbs light at 258 with a molar extinction co-efficient of 18,000. NAD abs

Question

NAD absorbs light at 258 with a molar extinction co-efficient of 18,000.

NAD absorbs light at 258 with a molar extinction co-efficient of 18,000. NADH absorbs light at 258 with a molar extinction co-efficient of 15,000 and also absorbs light at 340 with a molar extinction co-efficient of 6,220.You have prepared a mixed solution of NAD and NADU of unknown concentration. The absorbance of the mixture is 1.3 at 258 nm and 0.32 at 340nm. What is the concentration of NAD? of NADH? (express your answers in uM)

Explanation / Answer

A = c L

Concentration of NAD at 258nm

A (258) = c L

1.3 = 18000× c ×1 cm

C = 1.3/18000 L*mol-1*cm-1 = 7.22 ×10-4

C =1.3846 ×10-4 mol/L/cm

Concentration of NAD; C = 1.3846×10-11 umol/L/cm =1.3846×10-11 uM

Concentration of NADH at 258nm

A (258) = c L

1.3 = 15000× c ×1 cm

C = 1.3/15000 L*mol-1*cm-1 = 8.66 ×10-5

C =8.66 ×10-5 mol/L/cm

Concentration of NADH; C = 8.66 ×10-11umol/L/cm =1.3846×10-11 uM

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