The overall order of an elementary step directly corresponds to its molecularity

Question

The overall order of an elementary step directly corresponds to its molecularity. Both steps in this example are second order because they are each bimolecular. Furthermore, the rate law can be determined directly from the number of each type of molecule in an elementary step. For example, the rate low for step1 is The exponent"2" is used because the reaction involves two NO_2 molecules. The rate law for step 2 is because the reaction involves only one molecule of each reactant the exponents are omitted. Consider the following elementary steps that make up the mechanism of a certain reaction What is the overall reaction?

Explanation / Answer

1. 2X -----> Y + Z

2. Y + L ---> M + Z

overall reaction = Y will get cancelled in both the sides

remaining components are

2X + L ----> M + 2Z

what ever you written is correct but you forgot add both the Z's

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