Assume you are performing the calibration step of Experiment 8 and you begin wit

Question

Assume you are performing the calibration step of Experiment 8 and you begin with 50 g of water at 20 oC and 50 g of water at 80 oC. After adding the two portions of water into your calorimeter setup and following the procedure outlined in the experiment, you determine the temperature of the mixed portions of water to be 45 oC. What is the heat capacity of the calorimeter?
Assume room temperature is 25oC. Assume you are performing the calibration step of Experiment 8 and you begin with 50 g of water at 20 oC and 50 g of water at 80 oC. After adding the two portions of water into your calorimeter setup and following the procedure outlined in the experiment, you determine the temperature of the mixed portions of water to be 45 oC. What is the heat capacity of the calorimeter?
Assume room temperature is 25oC.
Assume room temperature is 25oC. Assume room temperature is 25oC.

Explanation / Answer

we know that

heat lost by hot body = heat gained by cold body

also

heat = m x s x dT

now

let the final temperature be Tf

so

now

heat lost by hot water = heat gained by cold water

m x s x dT for hot water = m x s x dT for cold water + ( C x dT ) for calorimeter

we know that

specific heat of water = 4.184

so

using those values

we get

50 x 4.184 x ( 80-45) = 50 x 4.184 x ( 45-20) + C x (45-25)

solving

we get

C = 104.6

so

the heat capacity of the calorimeter = 104.6 J/c

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.