In sediments and waterlogged soil, dissolved O2 concentrations arc so low that t

Question

In sediments and waterlogged soil, dissolved O2 concentrations arc so low that the microorganisms living mere must rely on other sources of oxygon for respiration Some bacteria can extract the oxygen in sulfate ions, reducing the sulfur in them to hydrogen sulfide gas and giving the sediments or soil a distinctive rotten-egg odor. What is the oxidation number of sulfur in those compounds?SO4 2 - (aq) Write the not ionic equation for the reaction under acidic conditions (H3O+) that releases O2 sulfate forms hydrogen sulfide gas. Use water as the reactant in the half-reaction that formation of oxygen.

Explanation / Answer

a)

SO4-2

Oxygen is typically charged as -2

substiute in redox equation:

S +4(-2) = -2

S = -2 + 8

S = +6

and for

H2S --

2H + S = 0

H = typically charged as +1

2(+1) + S = 0

S = -2

b)

net ionic equation of:

SO4-2 + H3O+ = H2S + O2

split:

SO4-2 = H2S

H2O = O2

balance O

SO4-2 = H2S + 4H2O

H2O + H2O = O2

blaance H

10H+ + SO4-2 = H2S + 4H2O

H2O + H2O = O2 + 2H+

balance charge

8e- + 10H+ + SO4-2 = H2S + 4H2O

H2O + H2O = O2 + 2H+ + 2e-

balance e-

8e- + 10H+ + SO4-2 = H2S + 4H2O

4H2O + 4H2O = 4O2 + 8H+ + 8e-

add all

8H2O + 8e- + 10H+ + SO4-2 = H2S + 4H2O + 4O2 + 8H+ + 8e-

cancel common terms

4H2O +2H+ + SO4-2 = H2S + 4O2

balance H3O+

2H2O +2H3O+ + SO4-2 = H2S + 4H2O + 4O2

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