Could someone please explain how to get the answer for this? I\'m just very conf

Question

Could someone please explain how to get the answer for this? I'm just very confused. Thank you in advance!

reactions of the enzyme system and reaction rate constants Table 1. Elementary Elementary reaction Reaction rate constant Reaction equation Binding of enzyme to substrate E S ES ES complex dissociation EST E S Catalytic formation of product ES E P cat Binding of enzyme to inhibitor E I EI ciation of El complex EI E I ib ES +I ESI Binding of ES complex to inhibitor tif ESI Dissociation of ESI complex E I

Explanation / Answer

Kcatis the rate constant of formation of product and enzyme from the enzyme-substrate complex. Kb is the rate constant of formation of substrate and enzyme from the enzyme-substrate complex.

Given Kcat is more than Kb. So, the rate of formation of product and enzyme from the enzyme-substrate complex is more than the rate of formation of substrate and enzyme from the same enzyme-substrate complex.

Therefore, when Kcat is more than Kb, enzyme will convert the substrate into product. The enzyme will be unchanged afterwards (option d).

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