online ksu.edu A mixture of 40 mL of methyl butyrate (MW 102.1 g/mol, d 0.89 g/m

Question

online ksu.edu A mixture of 40 mL of methyl butyrate (MW 102.1 g/mol, d 0.89 g/mL) and 10 mL butyric acid (MW 88.1 g/mol, d 0.96 g/mL) is distilled. Calculate the mole percent of each component, and using these mole percents and the figure below, answer the following questions: 1. What is the initial boiling point of this mixture? 2. What is the composition of the vapor in equilibrium with this liquid? What is the composition of the initial condensate from simple distillation? 3. Instead of a simple distillation, you set up a fractional distillation. Assuming three theoretical plates, what is the composition of the first fraction collected? 170 170 160 160 Gas 150 150 140 140 Temp (C) 130 130 120 120 Liquid 110 110 100 100 Mol% methyl butyrate 100 80 60 40 20 butyric acid 20 40 60 80 100

Explanation / Answer

I´ll answer the first question, if you want the others answer, attach them in a new question.

1)

105°C 80 methyl butyrate, 20 butyric acid.

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