Consider the EDTA titration of a 40.00 mL sample of 0.00713 M Cd2+ in a pH = 10

Question

Consider the EDTA titration of a 40.00 mL sample of 0.00713 M Cd2+ in a pH = 10 buffer. Calculate the concentration of Cd2+ in solution when 16.22 mL of 0.00867 M EDTA have been added to the solution. Please show work. Consider the EDTA titration of a 40.00 mL sample of 0.00713 M Cd2+ in a pH = 10 buffer. Calculate the concentration of Cd2+ in solution when 16.22 mL of 0.00867 M EDTA have been added to the solution. Please show work. Consider the EDTA titration of a 40.00 mL sample of 0.00713 M Cd2+ in a pH = 10 buffer. Calculate the concentration of Cd2+ in solution when 16.22 mL of 0.00867 M EDTA have been added to the solution. Please show work.

Explanation / Answer

millimoles of Cd+2 = 40 x 0.00713 = 0.2852

millimoles of EDTA = 16.22 x 0.00867 = 0.1406

reaction between Cd+2 and EDTA titration 1 : 1

millimoles of Cd+2 react with EDTA = 0.2852 -0.1406 = 0.1446

concentration of Cd+2   = millimoles reamins / total volume

                                      = 0.1446 / (40+16.22)

                                      = 0.00257 M

concentration of Cd+2 = 0.00257 M

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