An insertion mutation of 13 bp has occurred in exon 5 of gene that has 20 exons.

Question

An insertion mutation of 13 bp has occurred in exon 5 of gene that has 20 exons. the gene encodes for a protein with kinase activity. Of the following statements about the mutation and gene, which statement is most likely FALSE?

A. the mutation will change the reading frame in which the ribosome reads the mRNA coded by the gene.

B. the mutation was caused by splicing defect.

C. if the mutant polypeptide still functions as a kinase, ATP will be used as a substrate.

D. There is a high likelihood that the mutant polypeptide will be shorter thant the wild-type polypeptide.

E. the mutation will change the primary structure of the polypeptide encoded by the gene.

Explanation / Answer

the addition of 13 base pair will create a frame shift mutation due to which chain may terminate prematurely as the frame shift may create any stop codon. the addition of 13 base pair might be due to splicing defect, in which during the splicing the spliceosome may recognize the wrong base. Due to the frameshift mutation, the whole primary structure will be changed.   

So the false statement is option C - if the mutant polypeptide still functions as a kinase, ATP will be used as a substrate. since there is frameshift mutation there will be the formation of truncated protein which will be non-functional as its primary amino acids are changed

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