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Step by step pls What is the osmolarity of two liters of 1 M NaCl mixed with one

ID: 91823 • Letter: S

Question

Step by step pls What is the osmolarity of two liters of 1 M NaCl mixed with one liter of 3 M glucose? It is possible to compare the osmolarities of any two solutions simply by comparing their concentrations in osmoles/liter. To compare osmolarities, make sure the two solutions being compared have the same units, then compare numbers. Follow these rules: A. Find the total concentration of the resulting solution. B. Find the concentration of NaCL in moles. C. Find the concentration of NaCl in osmoles. D. Find the concentration of glucose in moles and osmoles.

Explanation / Answer

Answer:

A. Total concentration of resulting solution = 1M/2L NaCl + 3M/L of glucose = 0.5M/1L NaCl + 3M/L of glucose = 3.5M/L of both.

B. Concentration of NaCl in moles = concentration of NaCl in M per litre = 0.5 mol/L of NaCl = 0.5 mol/L.

C. NaCl dissociates completely in water to form Na+ ions and Cl ions. Thus, each mole of NaCl becomes two osmoles in solution: one mole of Na+ and one mole of Cl .

D. A solution of 1 L of 3 mole of Glucose has 3 mol/L of NaCl. A solution of 3 mol/L Glucose has an osmolarity of 1 Osmol/L.

To compare the two solutions:

Osmolarity of NaCl = 0.5 mol/L X 2 Osmol/mol = 4 Osmol/L

Osmolarity of Glucose = 3 mol/L X 1 Osmol/mol = 3 Osmol/L

So, glucose solution is a hypotonic solution compared to NaCl solution.

To find the osmolarity of the combined NaCl and glucose solutions:

Osmolarity of the combined solution = osmolarity of NaCl + Osmolarity of glucose = 4 Osmol/L of NaCl + 3 Osmol/L of Glucose = 7 Osmol/L.

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