A 15.7 g ice cube is placed into 318 g of water. Part A Calculate the temperatur

Question

A 15.7 g ice cube is placed into 318 g of water.

Part A

Calculate the temperature change in the water upon complete melting of the ice. Hint: Determine how much heat is absorbed by the melting ice and then use q=mCT to calculate the temperature change of the 318 g of water.

A 15.7 g ice cube is placed into 318 g of water.

Part A

Calculate the temperature change in the water upon complete melting of the ice. Hint: Determine how much heat is absorbed by the melting ice and then use q=mCT to calculate the temperature change of the 318 g of water.

Explanation / Answer

q absorbed by ice = q released by water.

mice*s*(0-T1) + n*DHfus = mwater*s*DT

mice = mass of ice = 15.7 grams

s = specificheat of ice = 2.010 j/g.c

DT = Chage in temperature =   c

n = no of mol of ice = 15.7/18 = 0.87 mol

DHfus of ice = 6.02 kj/mol

15.7*2.010*(T1-0) = 318*4.18*(T2-T1)

its necessary to know about the initial temperature of ice ,

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