morphine has the formula C17H19NO3. it is a base and accepts one proton per mole

Question

morphine has the formula C17H19NO3. it is a base and accepts one proton per molecule. it is isolated from opium. a 0.675 g sample of opium is found to require 8.94 mL of a 1.15*10^-2 M solution of sulfuric acid for neutralization. calculate the percent morphine in the opium sample morphine has the formula C17H19NO3. it is a base and accepts one proton per molecule. it is isolated from opium. a 0.675 g sample of opium is found to require 8.94 mL of a 1.15*10^-2 M solution of sulfuric acid for neutralization. calculate the percent morphine in the opium sample

Explanation / Answer

2 Morphine + H2SO4 --> 2 morphine(H) + SO4-2

Now all you need to do is calculate how many moles of H2SO4 was used:

1.15 x 10^-2 x 0.00894L = 0.000106 moles H2SO4

From the equation, we know that one H2SO4 reacts with 2 morphines so:

0.000106mole x (2morphine/1H2SO4) = 0.000213 moles morphine

Now we need to calculate the molecular weight for morphine:

(17 x 12.01) + (19 x 1.01) + 14.01 + (3 x 16.00) = 285.37g/mole

Now we can calculate how many grams of morphine was in the sample:

285.37g/mole x 0.000213mole = 0.0608g

Now we can get the percentage of morphine inthe sample:

100% x (0.0608/0.678) = 8.97% morphine

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