1- the molar mass of gas 1 is the double of the molar mass of gas 2. what is the

Question

1- the molar mass of gas 1 is the double of the molar mass of gas 2. what is the ratio of the distances travelled by these two gases?

2-suppose 3 opened bottles of vinegar (CH3COOH) and pentylamine (C5H13N) were placed next to each other, which would you smell first?

3- If the cotton ball containing the concentrated NH3 solution were inserted into the glass tube several seconds after the insertion of the cotton ball containing HCl, what effect would this have on the calculated value of the molecular weight of HCl?

Explanation / Answer

1) Distance travelled is inversely proportional to square root of molar mass.

Distance travelled by gas   1 / M1/2   , M = molar mass

Given that molar mass of gas 1 is the double of the molar mass of gas 2.

Let us assume, molar mass of gas 1 = 2 g/mol

molar mass of gas 2 = 1 g/mol

Hence,

  Distance travelled by gas 1/Distance travelled by gas 2 = (Molar mass of gas 2/ molar mass of gas 1)1/2

= (1/2)1/2

   = 1 : 1.414

Therefore,

ratio of distances travelled by two gases = 1 : 1.414

2) vinegar (CH3COOH) and pentylamine (C5H13N)

Gas with lower molar mass gives smell first.

Molar mass of vinegar = 60 g/mol

Molar mass of pentylamine = 87 g/mol

Therefore, vinegar gives smell first.

3)

The reaction taking place here is

ammonia + hydrogen chloride ---------> ammonium chloride

NH3 (g) + HCl (g) --------> NH4Cl (s)

Hence, molecular weight of HCl =  molecular weight of NH4Cl = 53.5 g/mol

So,  molecular weight of HCl increases.

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