Assume that air consists of 79% N2 and 21% 02 by volume. A closed vessel of 0.1

Question

Assume that air consists of 79% N2 and 21% 02 by volume.

A closed vessel of 0.1 m^3 capacity contains a mixture of methane (CH4) and air, the

air being 20% in excess of that required for chemically correct combustion. The

pressure and temperature in the vessel before combustion are, respectively, 3 bar and

100°C Determine:

(a) the individual partial pressures and the weights of methane, nitrogen and

oxygen present before combustion;

(b) the individual partial pressures of the burnt products, on the assumption that

these are cooled to 100°C without change of volume and that all the vapour

produced by combustion is condensed.

Answer

[(a) 0.2415, 2.179, 0.579 bar; 0.01868, 0.2951, 0.08969 kg

Co) 2.179, 0.2415, 0.0966 bar]

Explanation / Answer

partial pressure of a gas in a mixture of gases is the pressure which that gas would exert if it were the only gas present in that container. For calculating the partial pressure of individual gas find out the no. of moles of each and all then particularly divided by total and then multiplied by total pressure.

For the calculation of weight of gases use th equation PV=nRT where n (no. of moles = weight/ molecular weight )

P is pressure, V is volume , r is gas constant and T is temperature in kelvin.

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