12/5/2015 11:55 PM A 0/100 Gradebook Calculator Periodic Table Question 24 of 30

Question

12/5/2015 11:55 PM A 0/100 Gradebook Calculator Periodic Table Question 24 of 30 Map General Chemist Donald McQuanrie Peter A. Rock Ethan Gallogy University Science Books presented by Sapling Learning How many milliters of 10.5 M HCl(aq) are needed to prepare 260.0 mL of 1.00 M HCl(aq)? Number m L What is the concentration of a solution made by diluting 25 mL of 6.0 M HCI to a final volume of 750 mL? Number How many grams of chlorine gas are needed to make 340 × 106 g of a solution that is 1.50 ppm chlorine by mass? Number g CI, Previous Give Up & View Solution ) Check Answer 0 Next Exit Hint

Explanation / Answer

1) we know that

in both the cases moles of HCl should be the same

also

moles = molarity x volume

so

M1V1 = M2V2

10.5 x V1 = 1 x 260

V1 = 24.76

so

24.76 ml is needed

2)

M1V1 = M2V2

6 x 25 = M2 v 750

M2 = 0.2

so

the concentration is 0.2 M

3)

we know that

ppm = mg / kg

so

ppm = mass of chlorine (mg) / mass of solution (kg)

so

1.5 = mass of chlorine (mg) / 3.4 x 10^3

mass of chlorine = 5.1 x 10^3 mg

mass of chlorine 5.1 g

so

5.1 g Cl is required

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