if water had been in the pipet when you pipetted the vinegar, would the calculat
ID: 924459 • Letter: I
Question
if water had been in the pipet when you pipetted the vinegar, would the calculated molarity of acetic acid be:
lower M, higher M, or the same M
if water had been in the erlenmeyer into which you added the vinegar, would the calculated molarity of acetic acid be:
lower M, higher M, or same M
if water had been in the burr into which you poured NaOH solution, would the calculated molarity of acetic acid be:
lower M, higher M, same M
you pumped vinegar into a beaker to bring to your bench. if there had been water in that beaker, would the calculated molarity of acetic acid be:
lower M, higher M, same M
you took NaOH solution from a carboy into a beaker to bring to your bench. if there had been water in the beaker, would the calculated molarity of acetic acid be:
lower M, higher M, same M
Explanation / Answer
Dear Friend please have a look in the brackets for proper reason.
1. if water had been in the pipet when you pipetted the vinegar, would the calculated molarity of acetic acid be:
lower M (any compound on dilution its molarity decrease)
2. if water had been in the erlenmeyer into which you added the vinegar, would the calculated molarity of acetic acid be: lower M (any compound on dilution its molarity decrease)
3. if water had been in the burette into which you poured NaOH solution, would the calculated molarity of acetic acid be:same M (acetic acid reacts with NaOH to form sodium acetate, which acts as buffer in combination with acetic acid)
4. you pumped vinegar into a beaker to bring to your bench. if there had been water in that beaker, would the calculated molarity of acetic acid be: lower M (any compound on dilution its molarity decrease)
5. you took NaOH solution from a carboy into a beaker to bring to your bench. if there had been water in the beaker, would the calculated molarity of acetic acid be: same M (acetic acid reacts with NaOH to form sodium acetate, which acts as buffer in combination with acetic acid)
Thank you, all the best.
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