1. * Put in order from lowest to highest boiling point 0.17 m Ba(NO3)2 0.14 m Fe
ID: 926556 • Letter: 1
Question
1. * Put in order from lowest to highest boiling point0.17 m Ba(NO3)2 0.14 m Fe(CH3COO)2 0.15 m CrCl2 0.49 m Sucrose( nonelectrolyte)
2. A student measures the S2- concentration in a saturated aqueous solution of silver sulfide to be 2.99 x 10^-17 M The solubility product constant for silver sulfide is _____ 1. * Put in order from lowest to highest boiling point
0.17 m Ba(NO3)2 0.14 m Fe(CH3COO)2 0.15 m CrCl2 0.49 m Sucrose( nonelectrolyte)
2. A student measures the S2- concentration in a saturated aqueous solution of silver sulfide to be 2.99 x 10^-17 M The solubility product constant for silver sulfide is _____
0.17 m Ba(NO3)2 0.14 m Fe(CH3COO)2 0.15 m CrCl2 0.49 m Sucrose( nonelectrolyte)
2. A student measures the S2- concentration in a saturated aqueous solution of silver sulfide to be 2.99 x 10^-17 M The solubility product constant for silver sulfide is _____
Explanation / Answer
1) answer : 0.17 m Ba(NO3)2
explanation:
0.17 m Ba(NO3)2 -----------------> i = 3 , BP = 0.17 x 3 = 0.51
0.14 m Fe(CH3COO)2----------> i= 3 , BP = 0.14 x 3 = 0.42
0.15 m CrCl2 ------------------> i=3 , BP = 0.15 x 3 = 0.45
0.49 m Sucrose( nonelectrolyte)-------> i =1 , BP = 0.49
order of BP : 0.17 m Ba(NO3)2 >0.15 m CrCl2>0.14 m Fe(CH3COO)2 >0.49 m Sucrose( nonelectrolyte)
2)
Ag2S --------------------------------> 2Ag+ + S^-2
1.495x10^-17M 2.99 x 10^-17 M
Ksp = [Ag+]^2 [S^-2]
Ksp = (1.495x10^-17)^2 (2.99 x 10^-17)
Ksp = 6.68 x 10^-51
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