how would you make a 50 ml of a 10% acetic acid solution from a 30% acetic acid
ID: 926724 • Letter: H
Question
how would you make a 50 ml of a 10% acetic acid solution from a 30% acetic acid solution? (i.e., what volume of 30% stock solution and what volume of water would you use?) how would you make a 50 ml of a 10% acetic acid solution from a 30% acetic acid solution? (i.e., what volume of 30% stock solution and what volume of water would you use?) how would you make a 50 ml of a 10% acetic acid solution from a 30% acetic acid solution? (i.e., what volume of 30% stock solution and what volume of water would you use?)Explanation / Answer
According to law of dilution MV = M'V'
Where M = Molarity of stock = 30 % solution
V = Volume of the stock = ?
M' = Molarity of dilute solution = 10 % solution
V' = Volume of the dilute solution = 50 mL
Plug the values we get , V = ( M'V' ) / M
= ( 10 x 50 ) / 30
= 16.7 mL
Therefore the volume of stock solution taken is 16.7 mL
Also the volume of water added is = total volume of dilute solution - volume of stock solution taken
= 50 - 16.7
= 33.3 mL
So take 16.7 mL of the stock solution in a vessel & add 33.3 mL of distilled water to it we get required solution
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