Zn(s)+2HCl(aq)ZnCl2(aq)+H2(g) ( Find H rxn for this reaction as written.) (Use 1

Question

Zn(s)+2HCl(aq)ZnCl2(aq)+H2(g)

(Find Hrxn for this reaction as written.)

(Use 1.0 g/mL for the density of the solution and 4.18 J/gC as the specific heat capacity.)

Zinc metal reacts with hydrochloric acid according to the following balanced equation.

Zn(s)+2HCl(aq)ZnCl2(aq)+H2(g)

When 0.130 g of Zn(s) is combined with enough HClto make 53.4 mL of solution in a coffee-cup calorimeter, all of the zinc reacts, raising the temperature of the solution from 22.2 C to 23.9 C.

(Find Hrxn for this reaction as written.)

(Use 1.0 g/mL for the density of the solution and 4.18 J/gC as the specific heat capacity.)

Explanation / Answer

Zn(s)+2HCl(aq)----> ZnCl2(aq)+H2(g)

No of mol of Zn = 0.13/65.38 == 0.002 mol

volume of solution = 53.4 ml

mass of solution = 53.4 *1 = 53.4 grams

q released = m*s*DT

      = 53.4*4.18*(23.9-22.2)

       = 379.46 joule.

DHrxn = -q/n = -379.46/0.002 = -189730 joule

    = -189.73 kj/mol

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