For an isolated system, entropy will increase or stay the same. Entropy & Q: (a

Question

For an isolated system, entropy will increase or stay the same.

Entropy & Q:   (a small amount of heat dQ added to a system at temperature T)

For an ideal gas: S(E, V, N) = N k ln(V E3/2) + Const. = n R ln( V E3/2 ) + Const.

The absolute temperature is: for V held constant.

A) Consider n = 0.05 moles of an ideal gas at temperature T = 600 K. Calculate the change in entropy of the gas for a constant temperature process where the volume doubles. Show that your result agrees with the heat Q for this process.

B) Consider the same n = 0.05 moles of an ideal gas at temperature T = 300 K. Repeat question (B). Explain the similarities and differences between your answers.

C) Consider n = 0.05 moles of an ideal gas at temperature T = 300 K. Using the expression for the entropy of an ideal gas, calculate the change in entropy for a constant volume process that doubles the temperature of the gas.

D) Consider the constant volume process in D. Calculate the change in entropy for this process using the relation dS = dQ/T. Compare this result to what you found in D.

There are more questions, but I feel like I can figure it out once I get a little start/understanding of it.

Explanation / Answer

A) we know that

Entropy = dS =p dV/T

On integrating

S = n*R*ln(V_final/V_initial) = 0.05 X 0.0821 X ln (2V / V) = 0.00284

B) The change will be the same

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