Question 8 The purity of green crystal will be determined by a titration. This t

Question

Question 8

The purity of green crystal will be determined by a titration. This titration does not need an indicator because:

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Question 9

Sample % yield question: For the following reaction with the amount of reactants and molar masses given, if 18 g of C is produced, what is the % yield of this reaction? Answer to 2 sig figs. Sample input: if 20% is the correct answer, use 20 instead of 20% or a fraction such as 0.20.

A + B --> C

Molar masses: A = 100 g/mol; C = 200 g/mol

Starting materials: A = 10. g; B = In excess

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Question 10

Which of the following might be a contributing factor to low experimental purity of green crystals?

Explanation / Answer

The indicator is used for the colorless solutions and then titrates to get a colored solution.

The indicator is not used for the colored solutions as they are already colored.

Thus, the titration does not need for the determination of pure crystal, because KMnO4 is dark purple and any excessive KMnO4 will show its unique color in the titration.

Therefore, the last answer is correct.

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