Five isomeric compounds with the molecular formula C5H10O were analyzed by IR sp
ID: 930323 • Letter: F
Question
Five isomeric compounds with the molecular formula C5H10O were analyzed by IR spectroscopy. The fingerprint regions WERE NOT analyzed. Match each set of IR spectral data to the structure which is consistent with the data. (ONLY ONE structure for each IR data set. Not ALL structures will be used and no structure will be used more than one time.)
IR Spectra 1: A strong peak at 1710 cm IR Spectra 2: A strong, broad peak at 3430 cm1 but no peak at 1650- 1670 cm IR Spectra 3: A strong, broad peak at 3420 cm1 and a peak at 1600 cm IR Spectra 4: A peak at 1660 cm1 but no peak at 3300 3600 cm1 IR Spectra 5: No peaks at 3330 3600, 1650 1670, nor 1700- 1750 cm Possible Structures (only one structure per each IR spectra) OH OH OH DOMExplanation / Answer
C5H10O , degree of unsaturatin= ( nCx2+2 -nH) /2 = ( 2x5+2 -10) /2 =1 hence only 1 double bond or 1 ring present.
spectra 1 : Peak at 1710 cm-1 is C=O peak hence E
spectra 2: Peak at 3420 cm-1 correspnds to C-O strechc peak , hence D
spectra 3: peak at 3420 cm- is O-H peak and peak at 1600 cm-s corresonds to C=C hence H
spectra 4 : Peak at 1660 cm-1 corresponds to C=C , hence C
spectra 5 : A since no C=O , C=C , C-OH peaks , hence A
spectra 5 :
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