The energy levels of one electron ions are given by the equation E_n = (-2.18x10

Question

The energy levels of one electron ions are given by the equation E_n = (-2.18x10^-18 J)Z^2/n^2 where Z is atomic number and n is the energy level. The series in the He^+ spectrum that corresponds to the set of transitions where the electron falls from a higher level to the n_f = 4 state is called the Pickering series, an important series in solar astronomy Calculate the Pickering series wavelength associated with the excited state n_1 = 9. A = What region of the electromagnetic spectrum does this transition fall in

Explanation / Answer

Because we are dealing with an element other than hydrogen, it is necessary to introduce the atomic number Z into the equation.
E=(-2.18×10^-18 J)(Z^2 )[1/(ni^2 )-1/(nf^2 )]
E=(-2.18×10^-18 J)(2^2 )[1/(9 ^2 )-1/(4 ^2 )]=4.37346×10^-19 J

Plug the E value calculated into the equation: (wavelength is always positive)

E=hc/

4.37346×10^-19 J= hc/ (h= 6.62607004 × 10-34 j c =3x10^8 m/s)

=4.5451×10^-7 m

454.51 nm is in the visible spectrum

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.