Chromium(lll) oxide reacts with hydrogen sulfide (H_2S) gas to form chromium(lll

Question

Chromium(lll) oxide reacts with hydrogen sulfide (H_2S) gas to form chromium(lll) sulfide and water. Given an excess of H_2S(g), determine how many moles of O_2O_3 were used in the reaction if 378 g of Cr_2S_3(s) was produced and the reaction had an 80.0% yield. 1.51 mol 1.89 mol 2.36 mol Cr_203(s) + 3H_2S (g) rightarrow Cr_2S_ 3(s) + 3H_20 (l) 2.03 mol 7.05 mol How many grams of NaH2P04 are needed to react with 43.74 mL of 0.285 M NaOH? NaH_2PO_4(s) + 2NaOH(aq) rightarrow Na_3PO_4(aq) + 2H_2O(/) 0.748 g 1.496 g 0.720 g 0.677 g 1.321 g

Explanation / Answer

4.     = a  

5.       = b

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