Enter your answer in the provided box. Use ionization energy (scroll down to the

Question

Enter your answer in the provided box. Use ionization energy (scroll down to the first table below) and electron affinity values (scroll down to the second table below) to calculate the energy change (in kJ/mol) for the following reaction: kJ/mol The lonization Energies (kJ/mol) of the First 20 Elements First 1,312 2,373 520 899 801 1,086 1,400 1,314 1,680 Sixth ZElement 1 2 3 Second Third Fourth Fifth 5,251 7,300 1,757 2,430 2,350 2,860 3,390 3,370 11,815 14,85021,005 5 3,660 25,00032,820 4,620 4,580 5,300 6,0508,400 11,000 15,200 6,22038,000 47,261 7,500 7,47011,000 13,000 9,40053,000

Explanation / Answer

Na(g) + F(g) ---> Na+(g) + F-(g)

Na to Na+ , Ionization energy IE = 495.9 KJ/mol

F/F- electrona ffinity = -328 KJ/mol , EA will benegative since it represnets heat released in reaction.

Now total Energy = Na/Na+ ioniaton + F/F- electrona ffinity

         =   495.9 -328 = 167.9 KJ

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