Given the gas constant R = 0.08206 L atm/mol K Show all work. A student obtained

Question

Given the gas constant R = 0.08206 L atm/mol K Show all work. A student obtained the following data following the procedure of this experiment: The mass of the unknown The water bath temperature in K The barometric pressure in atmospheres The volume of the flask in liters The density of the vaporized unknown The molar mass of the vaporized unknown If a student doing this experiment did not completely evaporate the unknown before removing the flask from the water bath. the mass of the sample the student used in calculating the molecular mass was the molecular mass the student calculated was

Explanation / Answer

PV = nRT
.. n = m / M
.. PV = (m / M) RT..

M=mRT /PV

here P= 784 mmHg or 1.03 atm, T = 373.15 K, m= 0.569 g R= 0.08206 L atm / mol-KV= 0.212 L

M=0.569 g *0.08206 L atm / mol-K*373.15 K / 1.03 atm *0.212 L

M=79.79 or 79.8 g/mol

2 A

If evaporation in the experiment did not occur completely then the value of m be will be small.

B.

If evaporation in the experiment did not occur completely then the value of m be will be small and the molecular mass also small.

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