deb Map pling An open tubular chromatography column is 29.1 m long with an inner

Question

deb Map pling An open tubular chromatography column is 29.1 m long with an inner diameter of 0.571 mm. The inside wall is coated with a layer of 3.1 pum thick stationary phase. Unretained solute passes through the column in 3.76 min (tm), while a certain solute has a retention time of 18.90 min (t). A) What is the linear flow rate? B) What is the volume flow rate? Number Number Volume mL Linear flow rate 1.98 flow rate 7.74 min min. c) Calculate the retention factor, k D) Calculate the partition coefficient, K Number Number 186 4.02 E) What fraction of time did the solute spend in the stationary phase Number Fraction of time in the stationary phase 0.806 Incorrect

Explanation / Answer

C) Volume flow rate = 1.19 ml/min

D) Partition coefficient

K = k(Vm/Vs)

k = (18.90 - 3.76)/3.76 = 4.0266

Vm = 3.14 x (0.571)^2/4 x L = 0.256 mm^2.L

Vs = 3.14 x 0.571 x 0.0031 x L = 0.00556 mm^2.L

Partition coefficient K = 4.0266 x (0.256/0.00556) = 185

E) Fraction of time in the stationary phase = (18.9 - 3.76)/18.9 = 0.801 = 80.1%

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.