Which of the following statements is true? Which of the following complexes has

Question

Which of the following statements is true? Which of the following complexes has a coordination number of 6. Which of the following is the correct formula for potassium diaquatetrachloromolybdate (III)? Which of the following compounds can exhibit optical activity? Two platinum complexes of the formula Pt (NH_3)_2 Cl_2 have been studied. The hybrid orbitals are Which of the following complex ions would have tetrahedral geometry? The ion and corresponding color are correct except: Which of the following best describes the complex Fe (H_2 O_)_6 ^2+? A ligand is Molecules that have nonsuperimposable mirror images are

Explanation / Answer

Answer – 11) In this one we need to choose the true statements and there are option regarding the color of the hydrated solutions.

We know Cu2+ ion show blue color, Ni2+ show green color, Ag+ show colorless and Fe2+ ion show vary pale green color.

So statement A is the only true.

12) We know the coordination number is the number of ligand attached with central metal ion,

So we need to look for the compound which have total 6 ligand attached on the central metal ion

In the option number A and B there are 4 ligand attached with central metal ions respectively. D one has 5. The option C has there are 3 en ligands and we know en means ethylendaiammine which is bidentate ligand, so 3*2 = 6 bonds for with central metal ion, The outside of the braket ligands are secondary valancy, so it is not count in the coordination number ,so answer is –c) [Co(en)3](NO3)3.

13) In this one we are given the name potassium diaquatetrachloromolybdate(III). There is given molybdate(III) means there is Mo3+ and there are diaqua means 2 H2O and tetrachloro means 4 Cl . H2O is neutral ligand and 1 Cl = -1, so 4 Cl means 4- charge, so we need the charge one the complex is -1, we will get Mo3+ like

Mo + (0*2) * (-*4) = - 1

Mo = +3

So we need one potassium outside the bracket, so formula is K[Mo(H2O)2Cl4]

14) We know optically active compound has 4 different groups on the central atom. For the optically active compound has optical isomers and it is also when a molecule is not superimposable with its mirror image. So answer for this one is d) [Co(en)3]Cl3.

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