At a certain temperature, the equilibrium constant, Kc, for the following reacti

Question

At a certain temperature, the equilibrium constant, Kc, for the following reaction is 53.3.

At this temperature, 0.400 moles of hydrogen gas and 0.400 moles of iodine were placed in a 1.00 L vessel to react. What is the equilibrium concentration of HI?

At a certain temperature, the equilibrium constant, Kc, for the following reaction is 53.3. At this temperature, 0.400 moles of hydrogen gas and 0.400 moles of iodine were placed in a 1.00 L vessel to react. What is the equilibrium concentration of HI?

Explanation / Answer

Kc = [products]/[reactants] = [HI]^2/[H2]*[I2]

The molarity of each reactant will be the same as the number of moles, since it is a 1 L container.
So:

[HI]^2 = Kc*[H2]*[I2] = (53.3) * (0.400 M) * (0.400 M) = 8.52800 M
[HI] = 2.92027395975 M

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