Acetaminophen (acetyl-p-aminophenol, ApAP ) can be prepared from acetic anhydrid
ID: 934955 • Letter: A
Question
Acetaminophen (acetyl-p-aminophenol, ApAP) can be prepared from acetic anhydride (AA) and p-aminophenol (pAP). The molar mass of each is MMApAP, MMAA and MMpAP, respectively. If you start with an excess volume of acetic anhydride VAA of density ?AA and a limiting volume of p-aminophenol VpAP with the density of ?pAP and obtain a mass of acetaminophen mApAP, which equation from those listed below is the % yield of acetaminophen?
Acetaminophen (acetyl-p-aminophenol, ApAP) can be prepared from acetic anhydride (AA) and p-aminophenol (pAP). The molar mass of each is MMApAP, MMAA and MMpAP, respectively. If you start with an excess volume of acetic anhydride VAA of density ?AA and a limiting volume of p-aminophenol VpAP with the density of ?pAP and obtain a mass of acetaminophen mApAP, which equation from those listed below is the % yield of acetaminophen?Explanation / Answer
Abbreviations used in the solution:
Acetaminophen = ApAP, acetic anhydride= AA and p-aminophenol = pAP
molar mass of each is MMApAP, MMAA and MMpAP, respectively.
Volume of acetic anhydride used = VAA, density = dAA
Volume of p-aminophenol used = VpAP, density = dpAP
Mass of acetaminophen obtained = mApAP
The reaction scheme is:
AA + pAP ------> ApAP
1 mole of AA reacts with 1 mole of pAP to give 1 mole of ApAP.
As pAP is limiting reagent in this reaction,
moles of pAP used= moles of AA consumed during the reaction= moles of ApAP formed.
moles of pAP used= mass of pAP/Molar mass of pAP= (VpAP * dpAP)/ MMpAP
Thus,
the theoretical/ expected moles of ApAP to be formed = moles of pAP used = (VpAP * dpAP)/ MMpAP
Moles of ApAP experimentally obtained = mass of ApAP obtained/ Molar mass of ApAP
= (mApAP/ MMApAP)
Thus,
% Yield of ApAP in the reaction = (Experimental yield/ Theoretical yield)*100
= [(mApAP/ MMApAP)/ {(VpAP * dpAP)/ MMpAP} ]*100
= [(mApAP * MMpAP)/ (VpAP * dpAP * MMApAP) ]*100
The correct answer is the third option from top.
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