help!!! Before Beginning this experiment is the laboratory, you should be able t
ID: 936558 • Letter: H
Question
help!!!
Explanation / Answer
1. a. +5
b. +6
Explanation:
In AlPO4 having Al 3+ PO43- , hence Oxidation number of P is P5+ ( 5 + 4 (-2) = - 3
In Cr2O72- Oxidation number of Chromium is Cr6+ (( 2x 6 + 7x (-2)) = -2
2. Cathode
3.Oxidation occurs at anode and reduction occurs at cathode.
4.
i. Anode reaction Ni (s)/ Ni 2+ (aq):
the Ni metal loses mass becoming Ni+2 .... the nickel metal loses electrons, which makes it the stronger reducing agent
ii. Cathode reaction: Ag+ (aq)/ Ag (s):
the silver ions attract electrons, forming more silver metal, which makes the silver electrode gains in mass
iii. Standard Cell potential = 1.06V (Reduction pot - Oxidation pot )
iv. 2Ag{+}(aq) + Ni(s) --> 2Ag(s) + Ni{2+}(aq)
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