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Ethylene oxide (C_2H_4O) reacts with water to produce ethylene glycol (HOCH_2CH_

ID: 938006 • Letter: E

Question

Ethylene oxide (C_2H_4O) reacts with water to produce ethylene glycol (HOCH_2CH_2OH): C_2H_4O (aq) + H_2O(I) rightarrow HOCH_2OH(aq) In an experment at 20degreeC, the concentration of of C_2H_4O dissolved in 0.0076 M aqueous perchloric acid was observed to decreases over time as follows: Determine: a. The order of the reaction b. The rate constant k for the consumption of ethylene oxide c. The half-life or ethlene oxide, and d. The percentagve of the initial ethylene oxide that remains after one day.

Explanation / Answer

a)

from the data

the order of the reaction is first order.

b)

rate constant k = 1/t ln (Ao / At)

= 1/3 ln (0.150 / 0.132)

= 0.042 ks-1

rate constant k = 0.042 ks-1

c)

half - life t1/2 = 0.693 / k

t1/2 = 0.693 / 0.042

= 16.5 ks

half - life = 16.5 ks

d)

k = 1/t ln (Ao / At)

0.042 = 1 / 86.4 ln (0.150 / At)

At = 0.00398 M

percentage = (0.00398 / 0.15 ) x 100

= 2.65%

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