Calculations and unit conversions. Five grams of chlorine gas are contained in a

Question

Calculations and unit conversions. Five grams of chlorine gas are contained in a cylindrical container. The gas is at room temperature (298K) and pressure (1 atm). The molecular weight of chlorine is 35.45 g/mole. Assume the chlorine gas is an ideal gas. The height of the container is 2 cm. What is the radius of the container? Report your answer in both cm and ft. Equations to use: Ideal gas law: pV = NRT, where p=pressure, T=temperature, N=number of moles, R=gas constant, V=volume V_cylinder = A_base h Equations for a cylinder A_base = pir^2_base.

Explanation / Answer

T = 298 K P = 1 atm

MW = 35.45 g/mol

since Cl2 = 2*35.45 = 70.90 g /mol of Cl2

h = 2 cm = 0.02 m

R = ?

mol Cl2 = mass/MW = 5/70.9 = 0.07052 mol of Cl2

Apply

PV = nRT

V = nRT/P

V = (0.07052)(0.082)(298)/(1) = 1.723226 L

change to m3

V = 1.723226*10^-3 m3

then

V = PI*(R^2)*h

1.723226*10^-3 = (3.141592)(R^2)(0.02)

solve for R

R = sqrt((1.723226*10^-3)/(0.02)/(3.1592)) = 0.1651458 m

R = 16.5 cm

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.