(The pictures below have the lab procedure and chemical equations need) 1. Descr
ID: 938837 • Letter: #
Question
(The pictures below have the lab procedure and chemical equations need)
1. Describe the function of a phase transfer catalyst. Draw structure of the phase transfer catalyst used in this experiment. Why was a phase transfer catalyst necessary for this synthesis?
2.If 13C NMR were used to identify your product, the peak from which carbon would best distinguish the product from fluorene? Give the approximate chemical shift of such a peak.
3. Chromium(IV) reagents are known to be good oxidizing agents. However, chromium(IV) poses several health and environmental hazards. In a well-written paragraph, describe some of the health and environmental hazards of chromium(IV).
4. Picture below
The lab procedure is below.
The oxidation of fluorine proceeds by a free-radical mechanism. Near the beginning of the reaction the intermediate below is produced. Note the radical is located on the benzylic carbon. 4. Toluene, which also has a benzylic C, does not undergo air oxidation. Using resonance structures of the intermediate shown above, explain why fluorene is more likely to undergo oxidation by this pathway than will toluene. (3 pts.) Safety No
Explanation / Answer
1
oxidation of fluorine is in aqueous NaOH but fluorin is hydrophobic means it will not soluble in water
but in order to proceed the reaction smoothly all the starting material should soluble in water PHASE TRANSFER CATALYST will help to transfer the substrate from one phase to another phase
2)
CH2 which is there between the two phenyl group in starting material will be around at 37 ppm
where in product that oarticular product will be around at 190 ppm
3)
sorry for this i am not confidient
4)
radical formed in fluorine is stabilised by two phenyl groups it is more stable
where benzyl radical is stabilised by only one phenyl group
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